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some cleanup...
Signed-off-by: Alex A. Naanou <alex.nanou@gmail.com>
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parent
b06c5f05f8
commit
a507511378
21
ui/data.js
21
ui/data.js
@ -1787,7 +1787,7 @@ function sortImagesByFileName(reverse){
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}
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// Sort images while taking into account name sequence overflows
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// Sort images by name while taking into account sequence overflows
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//
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// A name sequence overflow is when file name sequence overflows over
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// *9999 and then resets to *0001...
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@ -1805,14 +1805,21 @@ function sortImagesByFileName(reverse){
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// number of files in set
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// XXX a simplification...
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//
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// NOTE: if any of the above conditions is not applicable this will
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// essentially revert to sortImagesByFileName(...)
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// NOTE: this will cut at the largest gap between sequence numbers.
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//
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// XXX it's also a good idea to write an image serial number sort...
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// XXX is this overcomplicated???
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//
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// NOTE: I like this piece if code, if it works correctly no one will
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// ever know it's here, if we replace it with the thee line dumb
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// sortImagesByFileName(...) then things get "annoying" every 10K
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// images :)
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function sortImagesByNameWithSeqOverflow(reverse, proximity){
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proximity = proximity == null ? 10 : proximity
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// sort and check names...
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// prepare to sort and check names...
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// NOTE: we do not usually have a filename seq 0000...
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if(DATA.order.length < 9999){
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var pattern = /....[0-9]{4}[a-z]?(\....[.])?/
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@ -1832,8 +1839,9 @@ function sortImagesByNameWithSeqOverflow(reverse, proximity){
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}
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// revert to normal sort my name...
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// XXX this is not needed but will make things faster...
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} else {
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return sortImagesByName(reverse)
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return sortImagesByFileName(reverse)
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}
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DATA.order.sort(cmp)
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@ -1842,9 +1850,6 @@ function sortImagesByNameWithSeqOverflow(reverse, proximity){
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// check if first and last are close to 0001 and 9999 resp.
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&& getSeq(DATA.order[0]) <= proximity
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&& getSeq(DATA.order[DATA.order.length-1]) >= 9999-proximity){
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console.log('fixing...')
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// find the largest gap position...
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var pos = null
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var gap = 0
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@ -1855,13 +1860,11 @@ function sortImagesByNameWithSeqOverflow(reverse, proximity){
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gap = n_gap
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}
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}
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// splice...
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// split and rearrange the order chunks...
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if(gap > proximity){
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DATA.order = DATA.order.splice(pos).concat(DATA.order)
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}
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}
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if(reverse){
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DATA.order.reverse()
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}
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